If 6x² - 17x + 12 = 0, then the solutions are?

x = 2/3, 4/3

x = 3/2, 4/3

x = 4/3, 2/3

None of these

Let's solve the quadratic equation 6x² - 17x + 12 = 0.

Using the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Here, a = 6, b = -17, and c = 12.

x = (17 ± √((-17)² - 4_6_12)) / (2*6)

x = (17 ± √(289 - 288)) / 12

x = (17 ± √1) / 12

x = (17 + 1) / 12 or x = (17 - 1) / 12

x = 18 / 12 or x = 16 / 12

x = 3/2 or x = 4/3

The solutions are x = 3/2 and x = 4/3.