There are two numbers such that the sum of the first and three times the second is 53, while difference between 4 times the first and twice the second is 2. What is the first number?

None of these

Given the equations:

x + 3y = 53 ... (1)

4x - 2y = 2 ... (2)

We can solve these equations using substitution or elimination. Let's use elimination.

Multiplying equation (1) by 2 and equation (2) by 3 to eliminate y:

2x + 6y = 106

12x - 6y = 6

Adding both equations:

14x = 112

x = 8