logx - 2log y = _____?
logx - 2log y = _____?
Explanation
Given log(x) - 2log(y):
Using logarithmic properties:
log(x) - 2log(y) = log(x) - log(y^2) = log(x/y^2)
Given log(x) - 2log(y):
Using logarithmic properties:
log(x) - 2log(y) = log(x) - log(y^2) = log(x/y^2)