If a sound note has intensity (I), equals to faintest audible sound (I₀), then will be it's sound level?
Answer: 0 dB
Explanation
The sound level β (in dB) is given by:
β = 10 log(I / I₀)
where I₀ is the threshold intensity (faintest audible sound). Given I = I₀:
β = 10 log(1) = 0 dB
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