In an isosceles triangle, the length of equal sides are 3x - 2y + 2 and x - y + 7. Find the value of x, if the sum of these sides is 12 cm?

In an isosceles triangle, the length of equal sides are 3x - 2y + 2 and x - y + 7. Find the value of x, if the sum of these sides is 12 cm?

Explanation

Given that the two sides of the isosceles triangle are equal:

3x - 2y + 2 = x - y + 7

This simplifies to:

2x - y = 5

The sum of the two equal sides is 12 cm:

(3x - 2y + 2) + (x - y + 7) = 12

This simplifies to:

4x - 3y = 3

Solving these two equations simultaneously, we find x = 6.