If point A is (4, –1) and point B is (3, 5), what is the square of the distance AB² between them?
Answer: 37
Explanation
To find the square of the distance between two points A(x1,y1) and B(x2,y2):
AB^2=(x2−x1)^2+(y2−y1)^2 =(3−4)^2+(5−(−1))^2
=(−1)^2+(6)^2
=1+36
=37
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