Find the largest number which divides 615 and 963 leaving remainder 6 in each case. | Important MCQ with Explanation

All-in-One Exam Prep Platform

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

60
80
None
87

Answer: 87

Explanation

we have to find the largest number which divide $615$ and $963$ leaving remainder $6$ in each case.

so let us subtract $6$ from $615$ and $963$

$\Rightarrow$ $615 - 6 = 609$

$\Rightarrow$ $963 - 6 = 957$

now lets find the $H C F$

$\Rightarrow$ prime factorisation of $609 = 29 \times 3 \times 3$

prime factorisation of $957 = 29 \times 3 \times 11$

now lets take out the common factors from both the cases

$\Rightarrow$ $29$ and $3$

$x = 29 \times 3 = 87$

∴ $87$ is the number which will divide $615$ and $963$ leaving remainder $6$ in each case.

****

RY18012023

This question appeared in Past Papers (2 times)

Junior Clerk Past Papers (1 times)

Junior Clerk Past Paper 15-11-2020 by STS

STS Past Papers (1 times)

STS Junior clerk Past Paper 15-11-2020

This question appeared in Subjects (1 times)

MATHS MCQS (1 times)

Basic Math

Install this app on your device for quick access right from your home screen.