How many different 4-student committees can be chosen from A panel of 12 students?
Answer: 495
Explanation
We need to choose a 4-student committee from a panel of 12 students. This is a combination problem, as the order of selection doesn't matter. We can use the combination formula:
C(n, k) = n! / (k!(n-k)!)
where n is the total number of students (12), k is the number of students to be chosen (4), and ! denotes the factorial function.
C(12, 4) = 12! / (4!(12-4)!)
= 12! / (4!8!)
= (12 × 11 × 10 × 9) / (4 × 3 × 2 × 1)
= 495
So, there are 495 different ways to choose a 4-student committee from a panel of 12 students.
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