Explanation

Let's assume the maximum marks in each subject are 100. Then, the student's total marks in the three subjects are:

75 + 80 + 85 = 240

If the marks of another subject are added, the total marks become:

240 + x (where x is the marks obtained in the fourth subject)

The average percentage cannot be less than 60% because:

• If the student scores 0 in the fourth subject, the total marks would be 240, and the average percentage would be (240/400) x 100% = 60%.
• If the student scores any marks in the fourth subject, the average percentage would be higher than 60%.

Explanation

Let man required =X

More men, less men (indirect proportion)

M= 15x10/3

M= 150/3

M= 50

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ND19-1-2023

Explanation

Let, the number be x.

Given, one-third of one-fourth of the number is 15.

Or, (1/3)(1/4)x = 15

So, x = 15*3*4 = 180.

Now, three-tenths of that number will be ,(3/10)x = (3/10)*180 = 18*3 = 54.

Explanation

Explanation

Let the product of two real numbers = ab

One number =9

9a=72

A= 72/9

A=8

Explanation

Let the number be x

Then,

⇔34x−13x=60

⇔5x12=60

⇔x=(60×125

)⇔x= 144

Explanation

The first and the most important function of management is Planning.

Planning involves setting objectives in advance, a goal which is to be achieved within a stipulated time.

ND5-09-2023

Explanation

For distribution between A & B the proportion has to be 2:3

Thus when A gets 2 units, B gets 3 units

So A gets ₹20/- & B gets ₹30/-

Distribution between B & C has to be 2:3

If ₹30 is 2, then 3 has to be ₹45/-

So ₹ 95,000/- to be divided between A, B & C shall have to be in the proportion of

20:30:45

Thus A gets ₹20′000/- B gets₹30′000/- and C gets ₹45000/-

Explanation

P1 = Rs.800

P2 = Rs.400

Time = 2 years

Difference in S.I. = Rs.40

Formula used:

S.I. = (PRT)/100

Calculation:

(P1RT)/100 – (P2RT)/100 = 40

⇒ RT(800 – 400) = 4000

⇒ R = 4000/800

⇒ R = 5%

∴ The rate of simple interest is 5%.

Explanation

In the figure, MN is the length of the ladder, which is placed against the wall AB and makes an angle of ${60}^{\circ }$ with the ground.
The foot of the ladder is at N, which is 2m away from the wall.
$\therefore BN=2m$
In right-angled triangle MNB :
$cos{60}^{\circ }=\frac{BN}{MN}=\frac{2m}{MN}$
$\Rightarrow \frac{1}{2}=\frac{2m}{MN}$
$\Rightarrow MN=4m$
Therefore, the length of the ladder is 4m.